Temporal value asymmetry
“participants … were asked to imagine that they had agreed to spend 5
hr entering data into a computer and to indicate how much money it would
be fair for them to receive. Some participants imagined that they had
completed the work 1 month previously, and others imagined that they
would complete the work 1 month in the future . . . Participants
believed that they should receive 101% more money for work they would do
1 month later (\(M = \$125.04\)) than
for identical work that they had done 1 month previously (\(M = \$62.20\)), \(t(119) = 2.22\), \(p = .03\), \(d =
0.41\)” (Caruso, Gilbert, and Wilson 2008,
797)
Plan a direct replication
- What is a plausible standard deviation? Hint: \(d = (M1 − M2)/SD\)
- What is an interesting minimal effect size (in $)?
- Simulate responses for 120 participants in total, assigned to either
the past or the future condition, assuming normal
distributions with the same variance. Use the standard deviation and the
minimal effect size from 1. and 2.
- Parameter recovery: Repeat the simulation from 3. 2000 times to
re-estimate the parameters (\(\mu_1, \mu_2,
\sigma\)) from the simulated responses. Visualize the recovered
parameters in box plots.
Hint: \(SE = 2/\sqrt{n} \cdot SD\),
where \(n\) is the total sample
size.
t <- t.test(x, y, mu = 0, var.equal = TRUE)
c(t$estimate, sd.pool = sqrt(n) / 2 * t$stderr)
- Power simulation: Increase the total sample size to find out the
n necessary for 80% power in the t-test.
- Power curves:
- Write an
R function that takes sample size
n, minimal effect d, standard deviation
sd, and number of replications nrep as
arguments. It should return the simulated power.
- Use this function to simulate the power for each combination of 4
different standard deviations and 4 sample sizes.
- Visualize these power curves in a single plot.
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